We're giving one lucky reader the chance to whisk their faves off to Koh Samui to live the sweet life. Simply enter our reader survey...
Looking to have some quality time with a group of your faves? Good news – we’ve got the ultimate luxury vacay up for grabs with a stay at Baan Jakawan in Koh Samui, Thailand, courtesy of The Luxe Nomad.
Valued at a whopping $7,500, one lucky family will enjoy the vacay of dreams with a three-day, two-night stay at luxury villa, Baan Jakawan. Let the kids run wild while you soak up the rays and a cocktail or two at the swim-up bar. And you don’t need to worry about lifting anything other than those cocktails during your stay because the villa comes complete with a personal chef, concierge, villa manager and housekeeper. Winning!
Once you’ve finished lazing by the pool, relax in the Thai-inspired living room complete with two sitting areas, so you can keep an eye on the kids but still have your own space. And then there are the bedrooms – you don’t need to fret too much about that invite list; there are eight incredible bedrooms to fill! So what do you need to do to be in with a chance of winning?
Simply enter our HoneyKids Reader Survey 2023!
To be in with a chance of winning this cool stay, enter our Reader Survey 2023 and tell us what you think about all things HoneyKids Asia. Enter by 11:59pm on 20 Feb 2023 – good luck! Full T&Cs are below.
Update: This giveaway has ended. Thanks for participating!
T&Cs: The prize is for three days and two nights. T&Cs will apply. The stay is valued for up to 16 pax for two nights. Guests need to pay separately for any additional night’s stay, meals, and other rental items or services. Valid until 31 Dec 2023. The prize is non-transferable and cannot be extended, resold, exchanged, or converted to cash. Prize may not be redeemed as an event venue. Blackout dates apply (the winner will be required to check with the reservations team).